Question

the area of a Trapezium is 138msquare .the distance and the difference between the lengths of the parallel sides are 12m and 7m respectively.find the lengths of the parallel sides​

Answer 1

Area of the trapezium =

2

1

×(sumofparallelsides)×h

138=

2

1

×(sum)×12

sum=

6

138

=23

∴a+b=23−−−−−−−(1)

Now the difference is given,

a−b=7−−−−−−−(2)

Adding equation (1) and (2)

2a=30

a=15

∴b=8