the area of a Trapezium is 180 cm square and its height is 9 cm. if one of the parallel side is longer than the other by 6cm ,find the two parallel sides
Ch name - area of a trapezium and a polygon
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Given,
Area of trapezium= 180 cm²
Height = 9 cm
Let,
Smaller parallel side= x cm
Then,
Larger parallel side= (x+6) cm
Now,
Area of trapezium= 1/2*(x+x+6)*9
180/9= 1/2*(2x+6)
20= x+3
x= 20-3
x= 17 cm
So,
Smaller parallel side= x= 17 cm
Larger parallel side= (x+6)= 17+6= 23 cm
Hope this helps you!
Area of trapezium= 180 cm²
Height = 9 cm
Let,
Smaller parallel side= x cm
Then,
Larger parallel side= (x+6) cm
Now,
Area of trapezium= 1/2*(x+x+6)*9
180/9= 1/2*(2x+6)
20= x+3
x= 20-3
x= 17 cm
So,
Smaller parallel side= x= 17 cm
Larger parallel side= (x+6)= 17+6= 23 cm
Hope this helps you!
akshatajay1410:
mark as brainliest if you find it helpful
thank you so much
happy
but from where this 3 came
In 20-3= x?
I transpositioned it
from x+3=20
no how 3 came there is only 6,9
so how
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