Question

The area of a trapezium is 180cm^2 and it's height is 9cm . If one of the parallel sides is longer than the other by 6cm, find the two parallel sides.​

Answer 1

Given

Let length of first parallel side X

Length of other parallel side is X + 6

Area of trapezium= 180 cm2

Let Height (h) =9 cm

We know that area of trapezium is

1/2 × (sum of parallel sides) × height

Therefore Area of trapezium is

1/2× (X + 6 +X) × 9 =180 cm2.

therefore 1/2 × (X + 6 +X) × 9 =180

⇒

1/2 × (2X + 6) × 9 =180

⇒ 2X + 6 = 180/2*2

⇒ 2X + 6 = 40

⇒2X = 40 – 6 =34

⇒X = 17

... Length of the parallel sides is X=17 cm and X + 6 = 17 + 6 = 23 cm.

Therefore lengths of the parallel sides are 17 cm, 23 cm

Answer 2

Step-by-step explanation:

The area of a trapezium

Therefore Area of trapezium is × (X + 6 +X) × 9

=180 cm2. Length of the parallel sides is X=17 cm and X + 6 = 17 + 6 = 23 cm. Therefore lengths of the parallel sides are 17 cm, 23 cm.

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