The area of a trapezium is 180cm^2 and its height is 9cm.If one of the parallel sides is longer than the other by 6cm,find the two parallel sides.
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The area of trapezium = 108cm^2
Let the shorter side by acm
The longer side = 6+acm
Height = 9cm
Ar. of trap. = 1/2(sum of two parallel side) x height
a+a+6 /2 x 9 = 108cm^2
2a+6/ x 9 = 108cm^2
9(2a+6)/2 = 108cm^2
18a+54 = 108 x 2
18a+54= 216
18a = 162 (subtracting 54 from 216)
a = 162 /18
a = 2cm
shorter side = a cm = 2 cm
longer side = a+6 = 8 cm
ShivanshDA2:
wrong answer
Answered by
1
Given,
Area =180 cm^2
Height=9 cm
Let the parallel sides be 'x' and 'x+6'
We know that,
Area of a trapizium = 1/2 × (sum of parallel sides)×height
Therefore, 180= 1/2×(x+x+6) × 9
=>180×2=(2x+6) ×9
=>360=18x+54
=>306=18x
=>17=x
HENCE, 1st parallel side=x=17cm
2nd parallel side =x+6=17+6=23cm
Hope this is helpful....
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