Question

the area of a trapezium is 1824 cm sq if the length of its parallel sides is 55 cm and 59 cm find the distance between them

Answer 1

Question :

The area of a trapezium is 1824 cm². If the length of its parallel sides are 55 cm and 59 cm, find the distance between them.

Answer :

$\sf\pink{Given:}$

• Area of Trapezium is 1824 cm² .

• Length of one of the parallel side is 55 cm.

• Length of the other parallel side is 59 cm.

$\sf\pink{To\:find:}$

• Distance between the parallel side in short height .

Explanation :

$\sf\red{Area\:of\:Trapezium = \dfrac{1}{2}\times ( a + b )\times h )}$

• a + b mean sum of parallel sides .

$\\ \longrightarrow\sf{ 1824 = \dfrac{1}{2}\times ( 55 + 59 )\times h}$

$\\ \longrightarrow\sf{1824 = \dfrac{1}{2}\times 114\times h}$

$\\ \longrightarrow\sf{ 1824 = 57\times h}$

$\\ \longrightarrow\sf{ h = \dfrac{1824}{57}}$

$\\ \longrightarrow\sf{ h = 32}$

• Therefore the height or the distant between the parallel sides of the Trapezium is 32 cm .

Answer 2

Answer:

32 cm is the height of trapezium

Step-by-step explanation:

Area of trapezium = 1824 (given)

Area of trapezium =1/2*(sum of 2 parallel sides) *h

1824 = 1/2 * (55+59)*h

1824 = 1/2 * 114*h

1824*2/114 =h

1824/57 = h

32 =h

Therefor the distance between two parallel line is 32 cm