Question

the area of a Trapezium is 210 centimetre square and its height is 14 cm if one of the parallel side is double that of the Other find the two parallel sides

Answer 1

we know that the formula for area of trapezium is 1/2×sum of parallel sides×distance.
so assume the parallel side x and 2x.
Then area=1/2×(x+2x)×14
210. =3x×7
210 =21x
x. =210/21
x. =10cm
so x=10cm
2x=2×10=20cm

Answer 2

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$Let \: the \: first \: parallel \: side = x \\ \\ Let \: the \: second \: parallel \: side = 2x \\ \\ Given \: that \: Area \: of \: trapezium = 210cm {}^{2} \\ \\ Height \: of \: trapezium = 14cm \\ \\ \\ As, \: we \: know \: that : \\ Area \: of \: trapezium = \frac{1}{2} \times b \times h \\ \\ = > 210 = \frac{1}{2} \times (2x + x) \times 14 \\ \\ = > 210 = 3x \times 7 \\ \\ = > 30 = 3x \\ \\ = > x = 10cm$

So ,The first parallel side is 10cm
and Second parallel side is 20cm..
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