Question

The area of a Trapezium is 210 CM square and its height is 14 cm if one of the parallel sides is double that of the other find that two parallel sides

Answer 1

Hi there !!

Area of trapezium = 210cm²
Height = 14cm

Let one of the parellal be x

Other parellal side = 2x

By applying the formula for the area of trapezium, the following equation will be formed.

We know,

Area of trapezium

$= \frac{1}{2} h(a + b)$

$210 = \frac{1}{2} \times 14(x + 2x)$

$210 \times 2 = 14(3x)$

$420 = 42x$

$x = \frac{420}{42}$
x = 10

Thus,

1st parellal side = x = 10cm

2nd parellal side = 2x = 2 × 10 = 20cm

Hence ,
the sides of the trapezium are 10cm and 20cm

Answer 2

Solution:

Given:The area of a Trapezium is 210 cm² and its height is 14 cm if one of the parallel sides is double that of the other.

let the length of a parallel side be x, then, the other is 2x.

Area of trapezium = $\frac{1}{2} h(a+b) sq.units$
                         210 = $\frac{1}{2} (14)(x+2x)$
                         210 =$7(3x)$
                      210/7 =3x
                           30 =3x
                           ∴x=10cm,.
                           ∴2x=2(10)=20cm
∴ The length of the parallel sides are 10cm and 20 cm respectively.

                           Hope it Helps