Question

The area of a trapezium is 210cm×cm and its height is 14cm. if one of the parallel sides is double that of the other, find the two parallel sides

Answer 1

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$the \: area \: of \: trapezium \: is \: equal \\ to \: - \frac{1}{2} (sum \: of \: parallel \: sides) \times h \\ the \: area \: is \: given \: = 210,height = 14 \\ one \: side \: is \: double \: to \: other \: so, \\ one \: is \: x \: and \: other \: is \: 2x \\ \frac{1}{2} \times (2x + x) \times 14 = 210 \\ \frac{1}{2} \times 3x \times 14 = 210 \\ 3x \times 7 = 210 \\ 3x = \frac{210}{7} = 30 \\ = x = \frac{30}{3} = 10 \\ \\hence ,one \: side\: is \: x = 10 \: and \: other \: \\ 2x= 20$