Question

The area of a trapezium is 210cm square and its heigght is 14 cm. If one of the parallel sides is double that of the other .find the two parallel sides.

Answer 1

let the one side be x and another 2x
height of trapezium 14 cm
area of trapezium = 1/2 × h ( a+b)
210 = 1/2 × 14 ( x+2x)
210 = 7 ( 3x)
210/7 =3x
30 =3x
x. = 30/3
x = 10
the one side of trapezium will be 10 cm and another side will be 2x =2×10
=20

Answer 2

Area of the trapezium is 210cm sq.

Height = 14cm

One parallel sides is double that of the other.

Let one parallel side be x.

x = 2x

Area of a trapezium = 1/2×sum of parallel side×height
= 1/2×(2x+x)×14cm

Given that area is 210cmsq.

1/2×(2x+x)×14cm = 210cmsq.
= 1/2×3x×14cm = 210cm sq.
=3x×7cm = 210cm sq.
= 21x = 210cm sq.
= x = 210/21cm
= x = 10cm

2x = 2×10cm
= 20cm

The two parallel sides are 10cm and 20cm.