Math, asked by ranawathimmatsingh68, 2 months ago

the area of a trapezium is 224 square and its height is 14 cm if one of the parallel side is longer than other by 8 cm find the length of two parallel sides​

Answers

Answered by EliteZeal
102

A n s w e r

 \:\:

G i v e n

 \:\:

  • Area of a trapezium is 224 sq. cm.

  • Height is 14 cm.

  • One parallel side is 8 cm longer than the other

 \:\:

F i n d

 \:\:

  • The length of two parallel sides

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S o l u t i o n

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  • Let the 2nd Parallel side be "x"

  • Hence the 1st Parallel side is "x + 8"

 \:\:

 \underline{\bold{\texttt{Area of trapezium :}}}

 \:\:

 \sf \dfrac { 1 } { 2 } \times h \times (l_{1} + l_{2}) ⚊⚊⚊⚊ ⓵

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Where ,

 \:\:

  • h = Distance between the parallel sides or height

  •  \sf l_{1 } = 1st Parallel side

  •  \sf l_{2} = 2nd Parallel side

 \:\:

 \underline{\bold{\texttt{Area of given trapezium :}}}

 \:\:

  • Area = 224 sq. cm.

  • h = 14

  •  \sf l_{1 } = x + 8 ⚊⚊⚊⚊ ⓶

  •  \sf l_{2} = x

 \:\:

Putting the above values in ⓵

 \:\:

 \sf 224 = \dfrac { 1 } { 2 } \times 14 \times (x + 8 + x)

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 \sf 224 = 7 \times (x + 8 + x)

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 \sf \dfrac { 224 } { 7 } = 2x + 8

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 \sf 32 = 2x + 8

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 \sf 2x = 32 - 8

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 \sf 2x = 24

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 \sf x = 12

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  • Hence one parallel side is 12 cm

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Putting x = 12 in ⓶

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 \sf l_{1 } = x + 8

 \:\:

 \sf l_{1 } = 12 + 8

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 \sf l_{1 } = 20

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  • Hence the other parallel side is 20 cm

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∴ The parallel sides of trapezium are 12 cm & 20 cm

Answered by Anonymous
68

Question :

The area of a trapezium is 224 square and its height is 14 cm if one of the parallel side is longer than other by 8 cm find the length of two parallel sides.ㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤㅤ

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Given :

  • Area of trapezium = 224cm²

  • Height of trapezium = 14cm

To find :

  • Length of two parallel sides.

Solution :

It's given that one of the parallel side is longer than other by 8 cm. So,

Let x be one one side.

Let Other side that is 8 cm longer.. = x+ 8

 \boxed {\tt Area \: of \: trapezium \: = \dfrac {1}{2} \times (sum \: of \: parallel \: sides) \times h }

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 : \implies \tt { 224 = \dfrac {1}{2} \times {(x + x + 8)} \times 14 }

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: \implies \tt {224 = 7 \times (2x + 8)}

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 : \implies \tt { \dfrac {224}{7} = 2x + 8}

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 : \implies \tt { 32 = 2x + 8}

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 : \implies \tt { x = 12 }

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↬One side, x = 12cm

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↬other side, x + 8 = 12 + 8 = 20 cm

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