Question

the area of a Trapezium is 240 CM² and its parallel sides are in the ratio of 2 :1. if the distance side is 10 CM then find the length of a parallel side​

Answer 1

Step-by-step explanation:

let parallel sides be of 2x and 1x cm

area= 1/2(sum of parallel sides) *distance between them

240=1/2*(2x+x)*10

240=5*3x

3x=240/5

x=48/3=16cm

2x=2*16=32cm

(PLEASE MARK BRAINLIEST)

Answer 2

Given is the area, the distance between parallel sides, and the ratio of the lengths of the parallel sides of a trapezium, Find the lengths of the parallel sides.

Explanation:

• The ratio of parallel sides is given to be $2:1$.
• Let there be a positive constant 'n'.
• Then the lengths of the parallel sides are given by $2n, n$.
• Let there be a trapezium having the distance between its parallel sides 'd' and the lengths of the parallel sides as 'a' and 'b'.
• Then the area of the trapezium is given by, $A=\frac{1}{2} (a+b)d$  
• Here we have, $A=240\ cm^2,\ d=10\ cm,\ a=2n,\ b=n$
• Hence we get,
•           $->A=\frac{1}{2} (n+2n)10\\->240=\frac{30n}{2} \\->n=16\ cm$  
• Now the lengths of the parallel sides are, $a=2n=32\ cm, \ \ b=n=16\ cm$  
• The lengths of the parallel sides for the given trapezium is found to be $32\ and\ 16\ cm$.