Question

the area of a Trapezium is 240 sq.cm and its height is 12 CM if one of the parallel sides is 30 cm what is the length of the other side​

Answer 1

Answer:

Given :-

• The area of a trapezium is 240 cm² and its height is 12 cm.
• One of the parallel sides is 30 cm.

To Find :-

• What is the length of the other side.

Formula Used :-

$\clubsuit$ Area Of Trapezium Formula :

$\footnotesize \bigstar \: \: \sf\boxed{\bold{\pink{Area_{(Trapezium)} =\: \dfrac{1}{2} \times (Sum\: of\: Parallel\: Sides) \times Height}}}\: \: \: \bigstar$

Solution :-

Let,

$\small \mapsto \bf Length\: of\: Other Side_{(Trapezium)} =\: b\: cm$

Given :

• Area of Trapezium = 240 cm²
• Height = 12 cm
• One parallel sides = 30 cm

According to the question by using the formula we get,

$\footnotesize \implies \bf Area_{(Trapezium)} =\: \dfrac{1}{2} \times (Sum\: of\: Parallel\: Sides) \times Height$

$\implies \sf 240 =\: \dfrac{1}{2} \times (30 + b) \times 12$

$\implies \sf 240 \times \dfrac{2}{1} =\: (30 + b) \times 12$

$\implies \sf \dfrac{240 \times 2}{1} =\: (30 + b) \times 12$

$\implies \sf 480 =\: (30 + b) \times 12$

$\implies \sf 480 \times \dfrac{1}{12} =\: 30 + b$

$\implies \sf \dfrac{480 \times 1}{12} =\: 30 + b$

$\implies \sf \dfrac{480}{12} =\: 30 + b$

$\implies \sf 40 =\: 30 + b$

$\implies \sf 40 - 30 =\: b$

$\implies \sf 10 =\: b$

$\implies \sf\bold{\blue{b =\: 10}}$

Hence, the required length of the other side is :

$\small \dashrightarrow \sf Length\: of\: Other\: Side_{(Trapezium)} =\: b\: cm$

$\small \dashrightarrow \sf\bold{\red{Length\: of\: Other\: Side_{(Trapezium)} =\: 10\: cm}}$

$\small \sf\bold{\purple{\underline{\therefore\: The\: length\: of\: other\: side\: of\: trapezium\: is\: 10\: cm\: .}}}$