Question

The area of a trapezium is 248 sq. m and its height is 8 m. If one of the parallel side
is smaller than the other by 4 m, find two parallel sides.
ho #wo parallel sides​

Answer 1

Answer:

area of trapezium= 248m²

height = 8m

let one of the parallel side be x metres.

then the other side will be x+4 metres.

$248 = \frac {1}{2} * (x + x+4) * 8\\\implies 248 = 4(2x + 4)\\\implies 248 = 8x + 16\\\implies 232 = 8x\\\implies x = 29m\\\\\\\therefore one\: parallel \:side = x = 29m\\and\: other \:parallel\: side\: is\: x=4 = 29+4 = 33m$

Answer 2

Answer:

The parallel sides are 33 m and 29 m.

Step-by-step explanation:

Given that, the Area of a trapezium is 248 sq. m

Its height, h is 8 m.

If the parallel sides are a m and b m and a>b then, a - b = 4 .  .  .  .  .  .  . (i)

Now, we know that, the Area of a trapezium $=\frac{a + b}{2} . h$

∴ $\frac{a + b}{2} . h = 248$

=> a + b = 2.(248)/8 = 62 .  .  .  .  .  .  .  .  .  (ii)

Adding equation (i) and (ii), 2a = 66 => a = 33

From equation (i), b = a - 4 = 33 - 4 = 29.