Question

The area of a trapezium is 248 sq. m and its height is 8 m. If one of the parallel side
is smaller than the other by 4 m, find two parallel sides.​

Answer 1

Step-by-step explanation:

The smaller side is 29 m and the longer side is 33 m

Step-by-step explanation:

Area of trapezium = \frac{1}{2} \times \text{Sum of parallel sides} \times Height21×Sum of parallel sides×Height

We are given that the area is 248 sq.m.

Height = 8 m

One of the parallel sides is smaller than the other by 4

Let the longer side be x

Smaller side = x-4

Now substitute the values in the formula:

248=\frac{1}{2} \times(x+x-4)\times 8248=21×(x+x−4)×8

248 \times 2 =(2x-4)\times 8248×2=(2x−4)×8

\frac{248 \times 2}{8} =2x-48248×2=2x−4

62 =2x-462=2x−4

62+4 =2x62+4=2x

66=2x66=2x

33=x33=x

So the longer side is 33 m

Smaller side = x-4 = 33-4 = 29 m

Hence the smaller side is 29 m and the longer side is 33 m

Answer 2

Answer:

sorry sister I don't know