Question

The area of a trapezium is 248 sq. m and its height is 8 m. If one of the parallel side
is smaller than the other by 4 m, find two parallel sides.​

Answer 1

$= > given \\ \\ = > area \: of \: trapezium = 248 \: sq \\ \\ = > height(h) \: = > 8cm \\ \\ = > area \: of \: trapezium = > \frac{1}{2}(sum \: of \: parallel \: sides) \times height \\ \\ = > 284 = > \frac{1}{2} (x + x - 4) \times 8 \\ \\ = > 248 = (2x - 4) \times 4 \\ \\ = > \frac{284}{4} = 2x - 4 \\ \\ = > 62 + 4 = > 2x \\ \\ 66 = 2x \\ \\ x = > \frac{66}{2} = > 33 \\ \\ x = > 33 \\ \\ hope \: its \: helpful \: buddy$

Answer 2

Area of trapezium= 248 m²

Area of trapezium= 248 m²Height (h)= 8 m

Area of trapezium= 248 m²Height (h)= 8 mLet the one parallel side be= x m

Area of trapezium= 248 m²Height (h)= 8 mLet the one parallel side be= x mOther parallel side =( x-4) m

Area of trapezium= 248 m²Height (h)= 8 mLet the one parallel side be= x mOther parallel side =( x-4) mArea of trapezium = 1/2 ( sum of parallel sides) × height

Area of trapezium= 248 m²Height (h)= 8 mLet the one parallel side be= x mOther parallel side =( x-4) mArea of trapezium = 1/2 ( sum of parallel sides) × height248 = 1/2 ( X+ X- 4)× 8

Area of trapezium= 248 m²Height (h)= 8 mLet the one parallel side be= x mOther parallel side =( x-4) mArea of trapezium = 1/2 ( sum of parallel sides) × height248 = 1/2 ( X+ X- 4)× 8248 = (2x - 4) × 4

Area of trapezium= 248 m²Height (h)= 8 mLet the one parallel side be= x mOther parallel side =( x-4) mArea of trapezium = 1/2 ( sum of parallel sides) × height248 = 1/2 ( X+ X- 4)× 8248 = (2x - 4) × 4248/4 = 2x-4

Area of trapezium= 248 m²Height (h)= 8 mLet the one parallel side be= x mOther parallel side =( x-4) mArea of trapezium = 1/2 ( sum of parallel sides) × height248 = 1/2 ( X+ X- 4)× 8248 = (2x - 4) × 4248/4 = 2x-462 = 2x-4

Area of trapezium= 248 m²Height (h)= 8 mLet the one parallel side be= x mOther parallel side =( x-4) mArea of trapezium = 1/2 ( sum of parallel sides) × height248 = 1/2 ( X+ X- 4)× 8248 = (2x - 4) × 4248/4 = 2x-462 = 2x-462+4= 2x

Area of trapezium= 248 m²Height (h)= 8 mLet the one parallel side be= x mOther parallel side =( x-4) mArea of trapezium = 1/2 ( sum of parallel sides) × height248 = 1/2 ( X+ X- 4)× 8248 = (2x - 4) × 4248/4 = 2x-462 = 2x-462+4= 2x66= 2x

Area of trapezium= 248 m²Height (h)= 8 mLet the one parallel side be= x mOther parallel side =( x-4) mArea of trapezium = 1/2 ( sum of parallel sides) × height248 = 1/2 ( X+ X- 4)× 8248 = (2x - 4) × 4248/4 = 2x-462 = 2x-462+4= 2x66= 2xX= 66/2

Area of trapezium= 248 m²Height (h)= 8 mLet the one parallel side be= x mOther parallel side =( x-4) mArea of trapezium = 1/2 ( sum of parallel sides) × height248 = 1/2 ( X+ X- 4)× 8248 = (2x - 4) × 4248/4 = 2x-462 = 2x-462+4= 2x66= 2xX= 66/2X= 33

Area of trapezium= 248 m²Height (h)= 8 mLet the one parallel side be= x mOther parallel side =( x-4) mArea of trapezium = 1/2 ( sum of parallel sides) × height248 = 1/2 ( X+ X- 4)× 8248 = (2x - 4) × 4248/4 = 2x-462 = 2x-462+4= 2x66= 2xX= 66/2X= 33One parallel side (X)= 33 m

Area of trapezium= 248 m²Height (h)= 8 mLet the one parallel side be= x mOther parallel side =( x-4) mArea of trapezium = 1/2 ( sum of parallel sides) × height248 = 1/2 ( X+ X- 4)× 8248 = (2x - 4) × 4248/4 = 2x-462 = 2x-462+4= 2x66= 2xX= 66/2X= 33One parallel side (X)= 33 mOther parallel side(x-4)= 33-4= 29 m

Area of trapezium= 248 m²Height (h)= 8 mLet the one parallel side be= x mOther parallel side =( x-4) mArea of trapezium = 1/2 ( sum of parallel sides) × height248 = 1/2 ( X+ X- 4)× 8248 = (2x - 4) × 4248/4 = 2x-462 = 2x-462+4= 2x66= 2xX= 66/2X= 33One parallel side (X)= 33 mOther parallel side(x-4)= 33-4= 29 m================================================================