Question

The area of a trapezium is 248 sq.m and its height is 8 m. If one of the parallel side
is smaller than the other by 4 m, find two parallel sides.
2 altitude is 10 dm​

Answer 1

Given:

Area of trapezium= 248 m²

Height (h)= 8 m

Let the one parallel side be= x m

Other parallel side =( x-4) m

Area of trapezium = 1/2 ( sum of parallel sides) × height

248 = 1/2 ( X+ X- 4)× 8

248 = (2x - 4) × 4

248/4 = 2x-4

62 = 2x-4

62+4= 2x

66= 2x

X= 66/2

X= 33

One parallel side (X)= 33 m

Other parallel side(x-4)= 33-4= 29 m

 

Answer 2

Given

• Area of trapezium= 258m²
• Height = 8m

To Find

• Length of Two parallel Side

Solution

Let The one side of parallel side be x cmthen the Other side be (x-4)cm

We know that,

$\implies \sf \: Area \: of \: Trapezium= \: \dfrac{1}{2} \times sum \: of \: parallel \: side \: \times \: heigth$

$\implies \sf \: 248= \: \dfrac{1}{2} \times x + x - 4 \: \times \: 8$

$\implies \sf \: 496= \: 2 x - 4 \: \times \: 8$

$\implies \sf \: 62= \: 2 x - 4 \:$

$\implies \sf \: 66 + 4= \: 2 x$

$\implies \sf \: x = \dfrac{66}{2}$

$\sf \: x =33m$

• One parallel side (X)= 33 m
• Other parallel side(x-4)= 33-4= 29 m