The area of a trapezium is 248 square metre and its height is 8 metre if one of the parallel side is smaller than other by 4 metre find two parallel sides
Answers
GIVEN :-
area of the trapezium = 248m²
height of the trapezium = 8m
Length of the parallel sides = ??
ATQ, one of the parallel sides of the trapezium is 4m less than the other.
let the greater one be x
therefore the smaller parallel side = x - 4
formula to find the area of a trapezium is 1/2 × h(b1 + b2)
where b1 and b2 are the parallel sides respectively.
➡ 1/2 × h(b1 + b2) = 248m²
➡ 1/2 × 8(x + x - 4) = 248m²
➡ 4(2x - 4) = 248m²
➡ 8x - 16 = 248m²
➡ 8x = 248 + 16
➡ 8x = 264
➡ x = 264/8
➡ x = 33m
hence, the length of the parallel sides are :-
- b1 = x = 33m
- b2 = x - 4 = 33 - 4 = 29m
VERIFICATION :-
= 1/2 × 8(33 + 29)
= 4 × 62
= 248cm²
hence verified!
ANSWER
Given:
Area of trapezium= 248 m²
Height (h)= 8 m
Let the one parallel side be= x m
Other parallel side =( x-4) m
Area of trapezium = 1/2 ( sum of parallel sides) × height
248 = 1/2 ( X+ X- 4)× 8
248 = (2x - 4) × 4
248/4 = 2x-4
62 = 2x-4
62+4= 2x
66= 2x
X= 66/2
X= 33
One parallel side (X)= 33 m
Other parallel side(x-4)= 33-4= 29 m
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Hope this will help you.....
