Math, asked by prerna2297, 7 months ago

# the area of a trapezium is 28 m?, and two parallel sides are 8 m and 60 dm
respectively, find the altitude.
1090 cm? and lengths of its parallel​

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Answers

Answered by aasthasharma1121
5

Answer:

Area of trapezium =1/2*altitude*(sum of parallel sides)

60dm = 6m

Area of trapezium= 28 (given)

28 = 1/2*altitude*(6+8)

28=1/2*altitude*14

28= 7*altitude

altitude=4m

=4m Answer

Answered by RAAZ34
2

Answer:

Step-by-step explanation:

Given

Area of trapezium =28m²

Two parallel sides=8m,60dm

Changing 60dm in meter

=6m (1m=10dm)

As we know area of trapezium =1/2 (sum of parallel lines) x altitude

28=1/2 x (8+6) x h

28=1/2x 14 x h

28=7 h

H=28/7 m

H=4m

This is ur ans hope it will help you

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