Question

The area of a trapezium is 300 cm square. The perpendicular distance between the two parallel sides is 15 m. If the difference of the parallel sides is 16 cm find the length of the parallel sides

Answer 1

300 = 1÷2 ×(a+a+16)×15
300= a+8×15
$300 \div 15 - 8$
ans = longer side =a+16=12+16=28m
shorter side=a=12m

Answer 2

Answer:

The parallel sides are 12 m and 28 m long

Step-by-step explanation:

Area of Trapezium = 300 cm sq.

Height of the Trapezium = 15 m

Difference of the parallel side = 16 cm

If one side is k , other side is   k-16.

Sum of parallel sides = 2k -16

Area = $\frac{1}{2} \times (\textrm{Sum of parallel sides}) \times (\textrm{Distance between them})$

$300 = \frac{1}{2}  \times 15 \times (2k -16)\\\\or, 2k -16 =  40 \\or, k= \frac{40 + 16}{2}$

⇒ k =  28 cm

So, the other side is (28 - 16) = 12 cm