Question

The area of a trapezium is 304 cm2 . If the lengths of the parallel sides are 34 cm and 42 cm, find the distance between them .

Answer 1

Area of trapezium
= 1/2 × (sum of parallel sides) × height

=> 304 = 1/2 × (34 + 42) × h

=> 304 = 1/2 × 76 × h

=> 304 = 38 × h

=> h = 304/38

=> h = 8

Answer :- 8 cm

Answer 2

Solution⤵️

Given,
area of trapezium=304cm^2
length of the parallel sides are 34cm and 42cm

to find: Height

Since,
area of trapezium=304cm^2
so,
1/2×h(a+b)=304
=>1/2×h(34+42)=304
=>1/2×76h=304
=>38h=304
=>h=304/38
=>h=8cm

therefore, distance between the two parallel sides is 8cm