The area of a trapezium is 315sqcm and the perpendicular distance between it's parallel sides is 20.4cm . What is the length of other side
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Let the parallel lines be a and b
Given that difference of them is 6 cm
=> a - b = 6
Now we know that area of a trapezium =
\frac{1}{2} (a+ b)h \\
So, here given that area = 120 and
height = 8
=>
\frac{1}{2} (a + b) \times 8 = 120 \\ \\ = > (a + b) \times 4 = 120 \\ \\ = > (a + b) = \frac{120}{4} \\ \\ = > (a + b) = 30
So a + b = 30
But we are given that a - b = 6
Adding them,
a + b + a - b = 30 + 6
=> 2a = 36
=> a = 36/2
=> a = 18 cm
Now a + b = 30
=> 18 + b = 30
=> b = 30 - 18
=> b = 12cm
So first parallel side = 18 cm
another = 12 cm
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