Question

The area of a trapezium is 34 cm² and its height is 4 cm. One of the parallel sides of the trapezium is 10 cm, find the other parallel side​

Answer 1

Area of trapezium=34cm²

$➠ Area \: of \: trapezium = \frac{1}{2} \times (l _{1} + l_{2}) \times h$

$➠34 = \frac{1}{2} \times (10 \times x) \times 4$

$➠34 = 20 + 2x$

$➠ \: x = 7$

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Answer 2

Given,

$Area \: of \: Trapezium = 34cm {}^{2}$

$Length \: of \: one \: parallel \: side = \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: a = 10cm$

$Let \: the \: length \: of \: other \: parallel \: side \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = b \: cm$

Now,

$Area \: of \: Trapezium = \frac{1}{2} (a + b) \times h$

$= 34 = \frac{1}{2} (10 + b) \times 4$

$34 = (10 + b) \times 2$

$34 = 20 + 2b$

$34 - 20 = 2b$

$14 = 2b$

$\frac{14}{2} = b$

$7 = b$

$b = 7$

∴ Length of other parallel side = 7cm.