Question

The area of a trapezium is 34 cm2 and the length of one of the parallel sides is 10 cm
and its height is 4 cm. Find the length of the other parallel sides.

Answer 1

$\underline{\green {\sf Given:- }}$

• Area of the trapezium = 34 cm.

• Length of one parallel side (a) = 10 cm.

• Height = 4 cm.

$\underline{\pink {\sf To\:Find:- }}$

• Length of other parallel side (b) = ?

$\underline{\orange {\sf Solution:- }}$

We know that,

$\large\boxed{\underline{{\sf  Area \:of \:the\: trapezium = \dfrac{1}{2} \times (a+b) \times h}}}$

$:\implies\:\:\sf {34=\dfrac{1}{2} \times(10+b)\times 4}$

$:\implies\:\:\sf {34=(10+b)\times 2}$

$:\implies\:\:\sf {17=10+b}$

$:\implies\:\:\sf {b=17-10=7\:cm}$

Answer 2

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$\sf\underbrace{ Question: }$

• The area of a trapezium is 34 cm² and the length of one of the parallel sides is 10 cm and its height is 4 cm. Find the length of the other parallel sides.

$\text{\large\underline{\red{Given:-}}}$

• Area of the trapezium = 34 cm.
• Length of one parallel side (a) = 10 cm.
• Height = 4 cm.

$\text{\large\underline{\orange{To\:Find:-}}}$

• Length of other parallel side (b) = ?

$\text{\large\underline{\purple{Solution :}}}$

Let the length of other parallel side = b cm

Now,

$\bf{Area\: of\: the \:trapezium}$=$\sf\dfrac{1}{2}$$\sf{(a + b)\: ×\:h}$

• $\implies$$\sf{34}=$$\sf\dfrac{1}{2}$$\sf{(10 + b)\:× 4}$

• $\implies$$\sf{34}=$$\sf{(10 + b)\:× 2}$

• $\implies$$\sf{34 =20 + 2b}$

• $\implies$$\sf{34 - 20 = 2b}$

• $\implies$$\sf{14 = 2b }$

• $\implies$$\sf{34 =20 + 2b}$

• $\implies$$\sf\dfrac{14}{2}$$\sf{ = b}$

• $\implies$$\sf{7 = b}$

• $\implies$$\sf{b = 7}$

$\large { \underline{ \boxed{ \textsf{∴ length\:of\:other\: parallel\:side\:= 7 cm}}}}$

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