the area of a Trapezium is 340 CM square if the length of its parallel sides are 35 cm and 50 cm find the distance between them
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area of trapezium =1/2 (a+b)h
a =35cm
b= 50cm
h=
340=1/2 (35+50)h
340=1/2×85×h
340×2/85=h
8 cm =h
8cm is the distance between parallel sides
a =35cm
b= 50cm
h=
340=1/2 (35+50)h
340=1/2×85×h
340×2/85=h
8 cm =h
8cm is the distance between parallel sides
Answered by
2
Area of trapezium is 1/2(a+b)h where a and b are parallel sides and h is height
So,
340 = 1/2(35+50)h
340*2 = 85h
680 = 85h
h = 650/85
h = 7.65 cm
Therefore the distance between two parallel sides is 7.65 cm
So,
340 = 1/2(35+50)h
340*2 = 85h
680 = 85h
h = 650/85
h = 7.65 cm
Therefore the distance between two parallel sides is 7.65 cm
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