Question

the area of a trapezium is 34cm and length of the one of the parallel sides is 10cm. height is 4cm. then the length of the other parallel side is

Answer 1

Given :

• Area of Trapezium = 34cm²
• Length of one parallel side = 10cm
• Height of Trapezium = 4cm

To Find :

• Length of other parallel side.

Solution :

$\longmapsto\tt{Let\:other\:parallel\:side\:be=x}$

Using Formula :

$\boxed{Area\:of\:Trapezium=\dfrac{1}{2}\times{Sum\:of\:parallel\:sides}\times{h}}$

Putting Values :

$\longmapsto\tt{34=\dfrac{1}{\cancel{2}}\times{(10+x)}\times{\cancel{4}}}$

$\longmapsto\tt{34=(10+x)\times{2}}$

$\longmapsto\tt{34=20+2x}$

$\longmapsto\tt{34-20=2x}$

$\longmapsto\tt{14=2x}$

$\longmapsto\tt{x=\cancel\dfrac{14}{2}}$

$\longmapsto\tt\bold{x=7cm}$

So , The length of other parallel side of the trapezium is 7cm...

Answer 2

Given:-

● Area of the trapezium= 34cm^2

● Length of one parallel side = 10cm

● Height of the trapezium = 4cm

Find out:-

■ The length of other parallel side

Formula used:-

$\leadsto{\tt{Area\: of \: Trapezium = \frac{1}{2}sum\: o f \: parallel\: sides × Height}}$

Solution:-

$\longmapsto{\tt{Area\: of \: Trapezium = \frac{1}{2}sum\: of \: parallel\: sides × Height}}$

$\longmapsto{\tt{34= \frac{1}{2}×(10+x)×4 }}$

$\longmapsto{\tt{34= (10+x)×4 }}$

$\longmapsto{\tt{34= 20+ 2x }}$

$\longmapsto{\tt{34-20 = 2x }}$

$\longmapsto{\tt{14=2x }}$

$\longmapsto{\tt{x =\cancel\frac{14}{2}}}$

$\longmapsto{\tt{x = 7 cm}}$

Hence, the length of the other parallel side is 7cm.