Question

the area of a trapezium is 34cm² and the length of one of the parallel sides is 10cm and it's height is 4cm. find the length of the other parallel side.​

Answer 1

☆ Given :

• Area of trapezium = 34 cm²
• Length of one parallel side = 10 cm
• Height of the trapezium = 4cm

☆ To find :

• The Length of the other parallel side.

☆ Solution :

Let the Length of other parallel side be x

We know that ,

${\underline{\boxed{\sf{Area_{(trapezium)}={\dfrac{1}{2}}\times{h}\times{(sum \ of \ parallel \ sides)}}}}}$

According to Question,

$\longmapsto\sf{34=}\dfrac{1}{\cancel{2}^1}\times{\cancel{4}^2}\times{(10+x)}$

$\longmapsto\sf{34=2}\times{(10+x)}$

$\longmapsto\sf{34=20+2x}$

$\longmapsto\sf{34-20=2x}$

$\longmapsto\sf{14=2x}$

$\longmapsto\sf\cancel\dfrac{14}{2}^{7}={x}$

$\longmapsto\sf{x=7cm}$

Therefore,

$\underline{\sf{The \ other \ parallel \ side \ = 7cm}}$

More formulas :

• $\sf{Area_(rectangle)=Length\times{Breadth}}$
• $\sf{Area_(square)=side^2}$
• $\sf{Area_(parallelogram)=base\times{height}}$
• $\sf{Area_(rhombus)=}\dfrac{D_1\times{D_2}}{2}$

Answer 2

★Question:-

the area of a trapezium is 34cm² and the length of one of the parallel sides is 10cm and it's height is 4cm. find the length of the other parallel side.

★Answer:-

★Given:-

Area of trapezium = $34cm ^{2}$

Length of 1st parallel Side = 10cm.

height = 4cm

★Find:-

Length of 2nd parallel side.

★Solution:-

$area \: of \: trapezium \leadsto \: {34cm}^{2} \\ \\ \leadsto \frac{1}{2} \times (sum \: of \: all \: sides) \times h = 34 \\ \\ \leadsto \: 20+2x = 34 \\ \\ \leadsto 2x = 34-20 \\ \\ \leadsto 2x = 14 \\ \\ \leadsto x = \frac{14}{2} \\ \\ \leadsto x=7$

★Final Answer:-

So, the 2nd Length of the trapezium is 7cm.