Question

The area of a trapezium is 368sqcm and the distance between the parallel sides is 16cm. If
one of the parallel side is of length 20cm.Find the length of the other side​

Answer 1

Given :

area of trapezium = 368sqm.

distance between parallel sides,height=16 cm

To Find :

length of the other side

Solution :

let the other side be x

$area \: of \: trapzium \: \\ = \frac{1}{2} \times( a + b) h$

$\implies \: 368 = \frac{1}{2} \times (20 + x)16 \\ \implies \: 368 \times 2 = 1 \times (20 + x)16 \\ \implies \: 736 = (20 + x)16 \\ \implies \: \frac{736}{16} = 20 + x \\ \implies \: 20 + x = 46 \\ \implies \: x= 46 - 20 = 26$

length of the other side of trapezium

$\green{ \boxed{26cm}}$

________________________

Answer 2

Answer:

Given :

Area of trapezium = 368 cm²

Height = 16 cm

One of the parallel sides = 20 cm

To Find :

Length of other parallel side

Solution :

We know that,

→ Area of parallelogram = 2 × Sum of parallel sides x Height

Let the other parallel sides be x :→ 368 = 1/2 × ( 20 + x) × 16

→ 368 = (20 + x) × 8

→ 20 + x = 368 / 8

→ 20 + x = 46

→ x = 46 - 20

⇒ x = 26

Other parallel sides = 26 cm