Question

The area of a trapezium is 380 sq. cm. If its parallel sides are in the ratio 3 : 5 and the perpendicular
distance between them is 19 cm, find the length of each parallel side.
​

Answer 1

Answer:

The parallel sides are 15cm and 25cm respectively.

Step-by-step explanation:

Given that,

Area of a trapezium is 380cm². It's parallel sides are in ratio 3 : 5 and the perpendicular distance between them is 19cm.

Here, the parallel sides are in ratio 3 : 5. So we need to find each parallel sides.

Step 1 :

Let's assume the parallel sides as "3x" and "5x" respectively.

We know that,

Area of a trapezium = ½(a + b)h

But, area is 380cm² (given)

So, 380 = ½(a + b) × h

Step 2 :

Solving for "x" :

→ 380 = ½(a + b) × h

→ 380 = ½ (3x + 5x) × 19

→ 380 = ½(8x)19

→ 380 = 4x × 19

→ 380 = 76x

→ 380/76 = x

→ 5 = x

∴ Value of ‘x’ is 5 cm.

Hence, the each parallel sides are :

• ‘3x’ = 3(5) = 15cm.
• ‘5x’ = 5(5) = 25cm.

Answer 2

Answer:

Answer:

The parallel sides are 15cm and 25cm respectively.

Step-by-step explanation:

Given that,

Area of a trapezium is 380cm². Its parallel sides are in a 3: 5 and the perpendicular distance between them is 19cm.

Here, the parallel sides are in a ratio of 3:5. So we need to find each parallel side.

Step 1 :

Let's assume the parallel sides as "3x" and "5x" respectively.

We know that,

Area of a trapezium = ½(a + b)h

But, the area is 380cm² (given)

So, 380 = ½(a + b) × h

Step 2 :

Solving for "x" :

→ 380 = ½(a + b) × h

→ 380 = ½ (3x + 5x) × 19

→ 380 = ½(8x)19

→ 380 = 4x × 19

→ 380 = 76x

→ 380/76 = x

→ 5 = x

∴ The value of ‘x’ is 5 cm.

Hence, each parallel sides are :

‘3x’ = 3(5) = 15cm.

‘5x’ = 5(5) = 25cm.