The area of a trapezium is 384 sq. cm. Its parallel sides are in the ratio 3 : 7 and the perpendicular distance between them is 12 cm. Find the length of the parallel sides
Answers
Answer:
Given:
Area of the trapezium =384 cm
2
The parallel sides are in the ratio 3:5 and the perpendicular height between them is 12cm.
Suppose that the sides are in x multiples of each other.
Then, length of the shorter side =3x
Length of the longer side =5x
Area of a trapezium =
2
1
×(Sum of parallel sides)×( Height)
⇒384=
2
1
×(3x+5x)×(12)
⇒384=
2
12
×(8x)
⇒384=6×(8x)
⇒8x=
6
384
=64
⇒x=
8
64
=8 cm
∴ Length of the shorter side =3×x=3×8=24 cm
And, length of the longer side =5×x=5×8=40 cm
Differnece between the length is 16 cm
Step-by-step explanation:
Given:
Area of the trapezium =384 cm
2
The parallel sides are in the ratio 3:5 and the perpendicular height between them is 12cm.
Suppose that the sides are in x multiples of each other.
Then, length of the shorter side =3x
Length of the longer side =5x
Area of a trapezium =
2
1
×(Sum of parallel sides)×( Height)
⇒384=
2
1
×(3x+5x)×(12)
⇒384=
2
12
×(8x)
⇒384=6×(8x)
⇒8x=
6
384
=64
⇒x=
8
64
=8 cm
∴ Length of the shorter side =3×x=3×8=24 cm
And, length of the longer side =5×x=5×8=40 cm
Differnece between the length is 16 cm