Question

the area of a trapezium is 384cm.if it's parallel sides are in the ratio 3:5 and the perpendicular distance between them be 12 cm, find the smaller of the parallel sides??????​

Answer 1

Here is the solution with answer .I hope it will help you.

Answer 2

let ratio between two parallel sides be x

therefore 1st side =3x,2nd side =5x

perpendicular side =12cm

area =(sum of two opposite sides)(perpendicular sides)

384=(3x+5x)(12)=8x×12

384=96x

x=384/96

x=4

so smaller parallel side =3x=3×4=12 cm