Question

the area of a trapezium is 420 m2 . the perpendicular distance between the two parallel sides is 121 m . if the difference of the parallel sides is 18 m, find the lengths of the parallel sides.

Answer 1

$\:\: \underline{\underline{\bf{\large\mathfrak{~~Solution~~}}}}$

let the length of the parallel sides are a and b

where b>a

now...

$420 = \frac{1}{2} \times 121 \times (a + b) \\ = > \frac{840}{121} = a + b \\ \\ and \: it \: is \: given \: that \: b - a = 18 \\ solving \\ \\ 2b = \frac{840}{121} + 18 \\ = > b = \frac{3018 }{2} = 1509 \: \: metre \\ \\ therefore.... \\ a = 1509 - 18 = 1491 \: \: metre$

Answer 2

Answer:

area of parallelogram = height*length

the distance between two parallel sides (height ) = 15 m

420= 15* length

divide with 15 on both sides

420%2F15+=15%2Alength%2F15

28= length

Result: Length = 28 m

Step-by-step explanation: