The area of a trapezium is 432m^2 the perpendicular distance between the two parallel sides is 18m if 5he difference of the parallel sides is 18m find the lengths of the parallel sides
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solution :-
area of trap.=1/2*height*(sum of both parallel sides)
let the smaller side be x, and according to the question the larger side will be 18m more than smaller ,thus:-
small parallel side=x
large parallel side =18+x
put values in formula
432=1/2*18(18+x+x)
432*2=18(18+2x)
864=324+36x
864-324=36x
540=36x
540/36=x
15=x
thus answer is :-
small side=15 m
large side=(15+18)m=33m
hope this helps
area of trap.=1/2*height*(sum of both parallel sides)
let the smaller side be x, and according to the question the larger side will be 18m more than smaller ,thus:-
small parallel side=x
large parallel side =18+x
put values in formula
432=1/2*18(18+x+x)
432*2=18(18+2x)
864=324+36x
864-324=36x
540=36x
540/36=x
15=x
thus answer is :-
small side=15 m
large side=(15+18)m=33m
hope this helps
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