Question

The area of a trapezium is 44 cm². If the parallel sides are in ratio 2:3. And it's height is 6 cm. Then, find the parallel sides​

Answer 1

Answer:

let the parallel sides be 2x and 3x

height = 6cm

area = ½×(b¹ + b²) ×h

44 =½ (2x+3x) 6

44 ×2 =( 5x )6

88/6 = 5x

14.66 =5x

14.66/5=x

2.93=x

2x =2 ×2.93

5.86

3x= 3 × 2.93

8.79

therefore the parallel sides measure = 5.86 and 8.79

it'll surely help you

Answer 2

${\huge{\underbrace{\overbrace{\color{aqua}{Question}}}}}$

The area of a trapezium is 44 cm². If the parallel sides are in the ratio 2 : 3 and its height is 6 cm. Then, find the parallel sides..

$\huge{\underline{\mathtt{\red{A}\pink{N} \green{S}\blue{W}\purple{E}\orange{R}}}}\red♡$

➙Area of trapezium = 44 cm²

➙Let, Parallel sides of the trapezium = 2x and 3x

➙Height of trapezium = 6 cm

➙Area of trapezium = $\frac{1}{2} \times \: (sum \: of \: parallel \: sides)\times h$

$➙44 \: \: {cm}^{2} = \frac{1}{2} \times (2x + 3x) \times 6$

$➙44 = \frac{1}{2} \times 5x \times 6$

$➙44 \times 2 = 5x \times 6$

$➙88 = 5x \times 6$

$➙\cancel \frac{88}{6} = 5x$

➙$14.66 = 5x$

$➙\frac{14.66}{5} = x$

$➙ \frac{ \cancel{1466}}{ \cancel{5} \times 10} = x$

$➙ \frac{29.32}{10} = x$

➙$2.93 = x$

➵Sides of the trapezium =

➙2x = 2 × 2.93 = 5.86

➙3x = 3 × 2.93 = 8.79