Question

The area of a trapezium is 44sq.cm and it's height is 4cm. Find the lengths of the two parallel sides if one side is shorter than the other by 2cm. ​

Answer 1

Answer:

are of trap. is =

$\frac{1}{2} \times height \times sum \: of \: parallel \: sides$

let short side is x

so long side is x+2

Step-by-step explanation:

now

$\ \frac{1}{2} \times 4 \times 2(x + 1) = 44 \\ 4(x + 1) = 44 \\ so \\ (x + 1) = 11 \\ x = 10$

so one side is 10cm and other sideis 12cm

Answer 2

Answer:

one of the side =b

longer side b+2, h=4cm

Area =h(I1+l 2) / 2

4 (b+b+2)/2 = 44

2b +2=88/4

2b +2=22

2b = 20

b = 10

so b +2=10+2=12

Sides are 12cm and 10cm