Question

The area of a trapezium is 475 cm square and the height is 19 cm find the length of its parallel sides of one side is 4 cm greater than the other by using heron's formula

Answer 1

let the first parallel side be X

then, the second parallel side =X+4

area of trapezium =1/2(sum of parallel sides)* height

=475=1/2(X+X+4)*19

=475=19/2(2x+4)

=475=19x+38

=475-38=19x

=437=19x

=437/19=X

=23

the first side=X=23

the second side=X+4

=23+4=27