Question

The area of a trapezium is 475 sq cm and the height is 19cm. Find the lengths greater than the other.​

Answer 1

Answer:

Let the length of smaller parallel side= x cm

then length of Larger parallel side=( x+ 4) cm

So, Area of trapezium= 1/2(sum of parallel side)* Height

=> 475= 1/2 (x+ x+4)*19

=> 475 = (x+2)*19

=> 25= x+2

=> x= 23 cm

so, smaller parallel side= 23 cm

Now, largest parallel side= 23+4= 27cm

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