Question

The area of a trapezium is 475cm^2 and the height is 19cm. Find the lengths of its two parallels sides if one side is 4cm greater than the other

Answer 1

are=475

let 1 parallel side=x and another is x+4

475=1/2*(sum of parallel sides)*h

475=1/2*(x+x+4)*19

475=19*x+38

x=23

1 side=23

2 side=27

Answer 2

Let length of one side is x cm

then length of other side will be (x + 4)cm [ a/c to question]

A/C to question,

height = 19cm

area of trapezium = 475cm²

but we know,
area of trapezium = 1/2 × (sum of length of parallel sides) × height

475 = 1/2 × (x + x + 4) × 19

475 =1/2 × (2x + 4) × 19

475 = (x + 2) × 19

25 = x + 2

x = 23 cm

hence, length of one side is 23cm
length of other side is (23cm + 4cm) = 27cm