The area of a trapezium is 475cm square and the height is 19m. Find the lengths of its two parallel sides if one side is 4cm greater than the other side.
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HERS the solution of Ur answer
Area is 475 cm². (given)
height = 19 cm. ( give )
let the || sides be x cm
one || side = x cm
another || side is 4cm.greater then the first
so another side = 4cm.× x
= 4Xcm.
We know that
The area of trapezium = (sum of the || sides) h
475 cm². = ( X. + 4 X ) 19 cm
= ( 5X cm. ) 19 cm
= 95X cm²
95X cm² = 475 cm.²
x = 475\95
x = 5 cm
so the first || side = x = 5 cm.
and another || side = 4x = 5 × 4 cm.
= 20 cm.
hope ull like it dear
TYNKS
HERS the solution of Ur answer
Area is 475 cm². (given)
height = 19 cm. ( give )
let the || sides be x cm
one || side = x cm
another || side is 4cm.greater then the first
so another side = 4cm.× x
= 4Xcm.
We know that
The area of trapezium = (sum of the || sides) h
475 cm². = ( X. + 4 X ) 19 cm
= ( 5X cm. ) 19 cm
= 95X cm²
95X cm² = 475 cm.²
x = 475\95
x = 5 cm
so the first || side = x = 5 cm.
and another || side = 4x = 5 × 4 cm.
= 20 cm.
hope ull like it dear
TYNKS
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