Math, asked by sarakshi96, 3 months ago

the area of a trapezium is 50cm² if the ratio of parallel sides is 2:3 and the difference between the parallel side is 10cm find the length of two parallel sides​

Answers

Answered by keshrimahendra647
0

late

Step-by-step explanation:

let the two parallel side between 2x and 3x respectively.

area of trapezium 50 cm

height 10cm

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Answered by sarita8421
40

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the area of a trapezium is 50 cm square if the ratio of parallel sides is 2 is to 3 and the difference between the parallel side is 10 cm find the length of two parallel side.

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>> the parallel side of trapezium is

  • (a) = 4cm
  • (b) = 6cm

★★let's find out !!

✰given:-

  • area of trapezium = 50cm²
  • parallel side 1st = (a) = 2x
  • parallel side 2nd = (b) = 3x
  • height = 10cm

★★using formula :

★★area of trapezium = ½ (a+b) ×h

★★so,

  =  > {50}cm^{2}  =  \frac{1}{2} \times (2x + 3x) \times 10

 =  >  \:  {50} \:  =  \frac{1}{2} (5x) \times 10

 = > 50 =  \: (5x) \times5

  = >  \frac{50}{5} = 5x

 = >   \: 10 = 5x

 =  > x =  \frac{10}{5}

 = >  \:  x = 2

✰✰★now,

★★side (a) = 2×2 = 4cm

★★side (b) = 3×2 = 6cm

༆★★hence the two parallel side is trapezium is 4cm and 6cm.★★

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