Math, asked by OalishaO, 2 months ago

The area of a trapezium is 512 cm², the distance between its parallel sides if the sum of the lengths of the parallel sides is 64 cm is ___________cm.
12

16

6

18


Please do explain how you did it.

Answers

Answered by snehitha2
10

Answer:

16 cm

Step-by-step explanation:

Given :

  • The area of the trapezium is 512 cm²
  • The sum of the lengths of the parallel sides is 64 cm

To find :

the distance between the parallel sides of the trapezium

Solution :

The area of the trapezium is given by,

A = ½ × h × (a + b)

where

h denotes the distance between the parallel sides

a and b denote the lengths of the parallel sides.

As given,

A = 512 cm²

a + b = 64 cm

Substitute the values,

512 = ½ × h × 64

512 = 32h

h = 512/32

h = 16 cm

Therefore, the distance between the parallel sides is 16 cm

Answered by CopyThat
4

Given

  • Area of a trapezium = 512 cm²
  • Sum of lengths of parallel sides = 64 cm

To find

  • Distance between the parallel sides

Solution

  • Area of trapezium = 1/2 h(a + b)

We are given with a + b and area of trapezium and are asked to find h.

  • 512 = 1/2 h(64)
  • 512 = 64/2h
  • 512 = 32h
  • h = 512/32
  • h = 16

Hence, the distance between the parallel sides is 16 cm.

Verification

  • Area = 1/2 h(a + b)
  • 512 = 1/2 16(64)
  • 512 = 16 (32)
  • 512 = 512
  • L.H.S = R.H.S
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