The area of a trapezium is 512 cm², the distance between its parallel sides if the sum of the lengths of the parallel sides is 64 cm is ___________cm.
12
16
6
18
Please do explain how you did it.
Answers
Answered by
10
Answer:
16 cm
Step-by-step explanation:
Given :
- The area of the trapezium is 512 cm²
- The sum of the lengths of the parallel sides is 64 cm
To find :
the distance between the parallel sides of the trapezium
Solution :
The area of the trapezium is given by,
A = ½ × h × (a + b)
where
h denotes the distance between the parallel sides
a and b denote the lengths of the parallel sides.
As given,
A = 512 cm²
a + b = 64 cm
Substitute the values,
512 = ½ × h × 64
512 = 32h
h = 512/32
h = 16 cm
Therefore, the distance between the parallel sides is 16 cm
Answered by
4
Given
- Area of a trapezium = 512 cm²
- Sum of lengths of parallel sides = 64 cm
To find
- Distance between the parallel sides
Solution
- Area of trapezium = 1/2 h(a + b)
We are given with a + b and area of trapezium and are asked to find h.
- 512 = 1/2 h(64)
- 512 = 64/2h
- 512 = 32h
- h = 512/32
- h = 16
Hence, the distance between the parallel sides is 16 cm.
Verification
- Area = 1/2 h(a + b)
- 512 = 1/2 16(64)
- 512 = 16 (32)
- 512 = 512
- L.H.S = R.H.S
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