Question

The area of a Trapezium is 520 cm and its parallel sides are 12cm and 14 cm long find its height

Answer 1

Area of trapezium = sum of parallel sides/2 × h
520 = (12+14)/2 × h
1040= 26 × h
h = 40 cm

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Answer 2

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SOLUTION:-




STEP BY STEP EXPLAINATION




Let the height be x cm



NOW ATQ,



AREA OF TRAPEZIUM=520cm(GIVEN)


Side1=12cm(GIVEN)


Side2=14cm(GIVEN)



AREA OF TRAPEZIUM=1/2×sum of parallel sides×height


$520 = 1 \div 2 (12 +1 6) \times x$


$520 = 1 \div 2 \times 26 \times x$


$x = 520 \div 13$

$x = 40$


THEREFORE,



HEIGHT OF TRAPEZIUM=40cm



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