Question

The area of a trapezium is 540〖cm〗^2. If the ratio of the parallel sides is 7:5 and the distance between them is 18 cm, find the lengths of the parallel sides

Answer 1

Area Of trapezium= 540 sq.cm

parallel sides=7:5

height=18cm

let the sides

->7x

->5x

area of trapezium=1/2 (sum of parallel sides) height

540=1/2 (7x+5x) 18

540=1/2×12x×18

12x= 540×2/18

12x= 60

x=5

so,

length of parallel sides=

7×5=35cm

5×5=25cm

Answer 2

$\huge \bf \pink{Hey \: there !! }$


▶ Given :-

→ Area of trapezium = 540 cm² .

→ Ratio of parallel sides $( b_1 \ratio b_2 )$ = 7 : 5 .

→ Distance between them [ h ] = 18 cm.


▶ To find :-

→ Length of parallel sides .


$\huge \red{ \mid \underline{ \overline{ \sf Solution :- }} \mid}$


Let the ratio of parallel side be x .

i.e., 7x and 5x .


$\sf \implies Area \: of \: trapezium = \frac{1}{2} (b_1 + b_2)(h). \\ \\ \sf \implies 540 = \frac{1}{2} (7x + 5x)(18). \\ \\ \sf \implies 540 = (7x + 5x) \times 9. \\ \\ \sf \implies \frac{540}{9} = (12x). \\ \\ \sf \implies12x = 60. \\ \\ \sf \implies x = \frac{60}{12} . \\ \\ \sf \therefore x = 5cm.$


✔✔ Hence, length of parallel sides are 35 cm and 25cm ✅✅ .


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