Question

The area of a trapezium is 540 cm². If the ratio of parallel sides is 7:5 and the distance between them is 18 cm, find the length of parallel sides.

Answer 1

areas of trapezium = 540 cm^2
height = 18 cm
it's parallel side ratio 7:5
let the 1 ratio be 7x
let the 2 ratio be 5x
area of trapezium = 2h (sum of parallel side )
540 =2×18 ×(7x +5x)
540 / 18 ×2 = 12x
60 = 12x
60 / 12 = x
5 = x
so it's parallel side 7x = 7× 5 =35
and 2 parallel side 5x = 5 ×5 =25

Answer 2

Given :

Area of trapezium = 540 cm²

So, let the length of parallel sides be 7x and 5x respectively.

So,

Area of trapezium = 540 cm²

⇒ 1 / 2 * ( a + b ) * h = 540

⇒ 1 / 2 * ( 7x + 5x ) * 18 = 540

⇒ 12x * 9 = 540

⇒ 12x = 60

⇒ x = 60 / 12

⇒ x = 5

Hence, the length of parallel sides are ;

7x = 7 * 5 = 35
5x = 5 * 5 = 25

Hence, the sides are 35 and 25.