Question

The area of a trapezium is 540cm2
, its parallel sides are in the ratio 7:5 and
perpendicular distance between parallel sides is 18cm. Find the lengths of its
parallel sides.
Section –

Answer 1

Answer:

area of ||gm = 1/2(sum of parallel sides)height

let the parallel sides be 7x and 5x

area =1/2 (7x+5x ) 18

1/2(12x)18

12x ×9 = 540

12x = 60

x = 5cm

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

area of trapezium = 540 cm^2

parallel side a = 7x

                                     ----- parallel sides in ratio 7:5

parallel side b = 5x

height = 18cm

area of trapezium = h(a+b)/2 = 540

                               = 18 (7x+5x) / 2 = 540

                               = 18 multiplied by 12x / 2 = 540

                               = 18 multiplied by 12x = 540 multiplied by 2

                               = 18 multiplied by 12x  = 1080

                                = 12x = 1080 / 18

                                = 12x = 60

                                 = x = 60 / 12

                                 = x =5

therefore, parallel sides are-

a = 7x = 7 multiplied by 5 = 35

b = 5x = 5 multiplied by 5 = 25