Question

the area of a Trapezium is 560 sq.ft CM the distance between the parallel side is 28 CM if one of them parallel side is is 17 cm find the length of a other side​

Answer 1

Answer:

altitude=14 cm

area of trap. = 560cm^2

one parallel line = x (let) and another =x+8

area of trap = 1/2×(sum of parallel side)×altitude=560cm^2

= 1/2×(x+x+8)×14=560cm^2

= 2x+8=80

= x= 76

one parallel side = x = 36

another parallel side (x+8)= 44

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Answer 2

Answer:

Given :-

• The area of a trapezium is 560 cm².
• The distance between the parallel sides is 28 cm.
• One of them parallel sides is 17 cm.

To Find :-

• What is the length of a other side.

Formula Used :-

$\clubsuit$ Area Of Trapezium Formula :

$\footnotesize \bigstar \: \: \sf\boxed{\bold{\pink{Area_{(Trapezium)} =\: \dfrac{1}{2} \times (Sum\: of\: parallel\: sides) \times Height}}}\: \: \: \bigstar$

Solution :-

Let,

$\mapsto \bf Other\: Parallel\: Sides_{(Trapezium)} =\: x\: cm$

Given :

• Area of trapezium = 560 cm²
• Distance between the parallel sides (Height) = 28 cm
• One of the parallel sides = 17 cm

According to the question by using the formula we get,

$\implies \sf 560 =\: \dfrac{1}{2} \times (17 + x) \times 28$

$\implies \sf \dfrac{\cancel{560}}{\cancel{28}} =\: \dfrac{1}{2} \times (17 + x)$

$\implies \sf 20 =\: \dfrac{1}{2} \times 17 + x$

$\implies \sf 20 \times \dfrac{2}{1} =\: 17 + x$

$\implies \sf \dfrac{20 \times 2}{1} =\: 17 + x$

$\implies \sf \dfrac{40}{1} =\: 17 + x$

$\implies \sf 40 =\: 17 + x$

$\implies \sf 40 - 17 =\: x$

$\implies \sf 23 =\: x$

$\implies \sf\bold{\red{x =\: 23\: cm}}$

$\therefore$ The length of a other parallel sides of a trapezium is 23 cm .