Question

The area of a trapezium is 720 cm^2. if the parallel sides are 7cm and 13cm long,find the distance between them

Answer 1

Answer:

Let and b are sides and d is the distance between them then

Area=1/2*(a+b)*d

720=1/2(7+13)*d

d=2*720/20

=72 cm

Answer 2

The distance between them is 72 cm

Step-by-step explanation:

Length of parallel sides are 7 cm and 13 cm

Area of trapezium = $\frac{1}{2}(\text{Sum of parallel sides}) \times Height$

Area of trapezium =$\frac{1}{2}(7+13)h$

The area of a trapezium is $720 cm^2$

So,.$\frac{1}{2}(7+13)h =720$

$h=\frac{720 \times 2}{20}$

h= 72 cm

Hence the distance between them is 72 cm

#Learn more:

Find the area of trapezium whose parallel sides are 25cm and 13cm long and the distance between them is 8 cm

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