Question

The area of a trapezium is 790 cm^2 . if the length of its parallel sides are 8 cm and 12 cm, find the perpendicular distance between them.

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Answer 1

Step-by-step explanation:

area of trapezium= (a+b)/2 × h

= (8+12)/2 × h = 790

= h = 790/10

h= 79cm

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Answer 2

Answer:

Perpendicular distance between parallel sides of trapezium is $79\ cm$ .

Step-by-step explanation:

To find : perpendicular distance between parallel sides of trapezium .

Given : the area of a trapezium is $790 \ cm^2$ . The length of its parallel sides are $8\ cm$ and $12 \ cm$ .

Solution :

• As per given data we know that , the area of a trapezium is

       $790 \ cm^2$.The length of its parallel sides are $8\ cm$ and $12 \ cm$ .

• Let , $x$  be the perpendicular distance between parallel sides of trapezium it is also called as height .
• Using following formula we find the perpendicular distance between parallel sides of trapezium ,
• Area of trapezium = $\frac{1}{2} \times ( sum \ of \ parallel\ sides ) \times height$

         $790 = \frac{1}{2} \times ( 8 + 12 ) \times x \\\\ 790 = \frac{1}{2} \times 20 \times x \\\\790 = 10\times x \\\\x = \frac{790}{10} \\\\x = 79\ cm$