Question

The area of a trapezium is 88 sq.cm, and its height is 8 cm. Then the sum of its parallel side is :

1. 10cm
2.11 cm
3.44cm
4.22cm​

Answer 1

Answer :

• Sum of Parallel sides = 22 cm.

Explanation :

Diagram :

$\setlength{\unitlength}{1.5cm}\begin{picture}(0,0)\thicklines\qbezier(0,0)(0,0)(1,2.2)\qbezier(0,0)(0,0)(4,0)\qbezier(3,2.2)(4,0)(4,0)\qbezier(1.5,2.2)(0,2.2)(3,2.2)\put(0.8,2.4){ \bf A }\put(3,2.4){ \bf D }\put(-0.3,-0.3){ \bf B }\put(4,-0.3){ \bf C }\put(4.4,0){\vector(0,0){2.2}}\put( 4.4, 0){\vector(0,-1){0.1}}\put(4.6,1){ \bf 8\ cm }\put(1, 1){ \bf Area = 88\ cm^2 }\end{picture}$

Given :

• Area of Trapezium = 88 sq.cm.
• Height of Trapezium = 8 cm.

To Find :

• Sum of its parallel sides.

Solution :

We know that,

Formula for Area of Trapezium,

Area = ½ × (sum of || sides) × h.

⇒ 1/2 × (sum of || sides) × 8 = 88 sq.cm.

⇒ 4(sum of || sides) = 88 sq.cm.

⇒ sum of || sides = 88 ÷ 4.

⇒ sum of || sides = 22 cm.

Therefore, Sum of || sides = 22 cm.

NOTE :-

If you are not able to see the diagram, then kindly see it from attachment.

Answer 2

Given:-

✦Area of the trapezium = 88 sq.cm

✦Height of the trapezium = 8 cm

To Find:-

✦Sum of the parallel side of the trapezium.

Solution:-

✦We have given that The area of the trapezium 88 sq.cm and height of the trapezium 8 cm.

✦To find the sum of parallel side of a trapezium using formula,

$\star{ \underline{ \boxed{ \sf{Area = \tt\frac{1}{2} \times \sf \: Sum \: of \: paralell \: side \times Height}}}} \star$

✦Let parallel side be x

$\\ \longmapsto \tt \: 88 = \frac{1}{2} \times x \times 8$

$\\ \longmapsto \tt \: 88 = \frac{1}{2} \times 8 \times x$

$\\ \longmapsto \tt \: 88 =4 \times x$

$\\ \longmapsto \tt \: \frac{88}{4} = x$

$\\ \longmapsto \tt \:x = 22 \: cm$

✦Option d is correct.

✦Hence, Sum of parallel side is 22 cm