the area of a trapezium is 897 sq.m if the parallel sides are of length 32m and 46m what is the distance between the parallel sides
Answers
Answered by
36
Distance between the parallel sides means height of the trapezium., let height be h
Area of a trapezium = 1/2 x h x ( sum of parallel sides)
897 = 1/2 x h x (32 + 46)
897 = 1/2 x h x 78
897 = 39h
h = 897/39
h = 23 m
So, distance between the parallel sides is 23 m
Area of a trapezium = 1/2 x h x ( sum of parallel sides)
897 = 1/2 x h x (32 + 46)
897 = 1/2 x h x 78
897 = 39h
h = 897/39
h = 23 m
So, distance between the parallel sides is 23 m
Answered by
33
Area of trapezium = 1/2 × (sum of parallel sides)×height
Given ;
Area = 897 sq.m
parallel sides = 32m & 46 m
h = ?
897 = 1/2 × (32+46) × h
897 = 78/2 × h
h = 897/39
h = 23
hence the distance between parallel sides is 23m .
Given ;
Area = 897 sq.m
parallel sides = 32m & 46 m
h = ?
897 = 1/2 × (32+46) × h
897 = 78/2 × h
h = 897/39
h = 23
hence the distance between parallel sides is 23m .
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