Question

The area of a trapezium of height 4 cm is 16 cm².If one of the parallel sides is 4 cm,the other side will be:
(explain in detail)​

Answer 1

Answer:

4cm

Step-by-step explanation:

Let the other side be x

One side=4cm

Height=4cm

Area=1/2×(4+x)×4

16=1/2(4+x)×4

x=4cm

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Answer 2

${\huge{\underline{\boxed{\red{\mathcal{Answer}}}}}}$

Given:

• Area of trapezium = 16cm^2
• Height = 4cm
• Length of one parallel side = 4cm

To Find:

• Length of other parallel side

Solution:

$\setlength{\unitlength}{1.5cm}\begin{picture}\thicklines\qbezier(0,0)(0,0)(1,2.2)\qbezier(0,0)(0,0)(4,0)\qbezier(3,2.2)(4,0)(4,0)\qbezier(1.5,2.2)(0,2.2)(3,2.2)\put(0.8,2.4){ \bf A }\put(3,2.4){ \bf D }\put(-0.3,-0.3){ \bf B }\put(4,-0.3){ \bf C }\put(4.4,0){\vector(0,0){2.2}}\put( 4.4, 0){\vector(0,-1){0.1}}\put(4.6,1){ \bf 4\ cm }\put(0, -0.5){\vector(1,0){4}}\put(0, -0.5){\vector( - 1, 0){0.1}}\put(1.7, - 0.9){ \bf x\ cm }\put(0.8, 2.8){\vector(1,0){2.5}}\put(0.8, 2.8){\vector( - 1, 0){0.1}}\put(1.7, 3){ \bf 4\ cm }\end{picture}$

$\text{We know that,}\\\longrightarrow</p><p>Area\: of \:a \:trapezium = \dfrac{1}{2} * (sum\:of\:parallel\:sides) * height. \\So,\\\\\implies 16cm^2 = \dfrac{1}{2\!\!\!/_{\:\:_1}} * (4+x) * 4\!\!\!\!/^{^\:\:\:\:\:2} \\\\\implies \dfrac{16}{2} = 4 + x \\\\\implies 4 + x = 8 \\\\\bf{\implies x = 4cm}$

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